The measure of angle P is 90 degrees.
The answer will depend on the location of the points B, P and C.
angle P
The complement of an angle can be added to that angle to get a total of 90 degrees. Therefore, if your angle was 45*, set up a simple algebra problem. 45+x=90 subtract 45, you get x=45 The complement of a 45* angle is 45*. The complement of a 30* angle is 60, etc. The supplement of an angle can be added to said angle to get a total of 180 degrees, so if your angle is 45*, set up an algebra problem (again :P). 45+x=180 subtract 45, x=135. The supplement of a 45* angle is 135*. The supplement of a 30*angle is 150*, etc. Hope this helped!
l M l l Q____l____ N lO l l l P Let MP & NQ be lines intersecting at O. Then angle MON + angle NOP = 180 degrees (linear pair) Angle MOQ + angle QOP = 180 degrees (linear pair) Adding the equations, Angle MON + Angle NOP + Angle MOQ + Angle QOP = 180 + 180 degrees = 360 degrees. Therefore all angles around O sum upto 360 degrees.
Definition of angle bisector:An angle is formed by two rays with a common endpoint. The angle bisector is a ray or line segment that bisects the angle, creating two congruent angles. To construct an angle bisector you need a compass and straightedge.Definition of midpoint:Midpoint of a line segment is the point that is halfway between the endpoints of the line segment. A line segment has only one midpoint. If AB is a line segment and P is the midpoint, then AP = BP =
Angle q will be less than 90 degrees because a right angle is 90 degrees and the 3 angles in a triangle add up to 180 degrees.
By using trigonometry or using Pythagoras' theorem for a right angle triangle.
55 - 20 = 35
<p><p> 180-x=3(90-x)-60 180-x=270-3x-60 3x-x=270-180-60 2x=30 x=15
if you read this you smell :p
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
the f-p-f bond angle is 120the cl -p-cl bond angle is 180and the f - p - cl bond angle is 90
Electrical angle is half of mechanical angle in unipolar electrical machines. In multipolar electrical machines, the relationship between the mechanical angle and electrical angle is Electrical angle = (P/2) x Mechanical angle where: P = Number of poles.
Assuming the angles are expressed in degrees: P = 2Q -3° (because "angle P is three less than twice the measure angle Q") P + Q = 180° (because they are supplementary angles) P+Q = 2Q - 3° + Q = 3Q -3° = 180° 3Q = 183° Q = 61° P = 2∙61° -3° = 122° - 3° = 119° If the angles are expressed in radians, the math is similar except you start with P = 2Q - 3 and P+Q = π yielding P = 2π/3 -1 and Q = π/3 +1
Sum of all three angles is 180 degrees. p = 36 so q+r = 180-36 = 144 degrees. Now, q = 5r so 144 = q+r = 5r+r = 6r so r = 144/6 = 24 and then q = 5r = 5*24=120 Answer: q = 120 deg, r = 24 deg
The answer will depend on the location of the points B, P and C.
"abcd is not a parallelogram or it does not have any right angles." ~(P and Q) = ~P or ~Q