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Q: Are numbers divisible by their multiples or factors or both?

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Multiples of 18.

Since both 3 and 5 are prime numbers, only numbers that are multiples of its product are the numbers that are divisible by both. 15 is the LCM of 3 and 5 and hence all multiples of 15 are divisible by both 3 and 5

All numbers that are multiples of 12 are divisible by both 3 and 4.

Any number divisible by 15

2275 is the smallest number that is divisible by both 175 and 325. All multiples of 2275 are divisible by both these numbers. Ex: 2275 4550 6825 9100 and so on...

Four. 24 and its multiples.

3 and all of its multiples.

Multiples of 6.

All the multiples of 4 are also multiples of 2.

The numbers divisible by both 3 and 4 are multiples of 12, thus between 10 and 99: 12, 24, 36, 48, 60, 72, 84, 96 are the numbers divisible by both 3 and 4.

They're both whole numbers. Factors go into numbers, numbers go into multiples. They have an inverse relationship. If A is a factor of B, then B is a multiple of A.

There are 12 multiples of 77 in that range.

All multiples of 6 are evenly divisible by 6, such as: 6, -6, 12, -12, 18, -18, and so on. Numbers divisible by six must also be divisible by both 2 and 3.

33 multiples of 3 10 multiples of 10 -3 multiples of both 40 total

I think you probably have your terms mixed up. You meant to ask, "What numbers are multiples of 3 and 4?". This answer would be anything that is divisible by both 3 and 4.Ex: 12, 24, 36 ect.There are no common factors of 3 and 4. A common factor would be a number that both numbers are divisible by. An example of this would be the numbers 12 and 30. The common factors of 12 and 30 are: 2, 3, and 6.

7 and 14 both fit that description.

The common multiples of 2 and 5 are 10, 20, 30, 40, etc.In detail:A common multiple is a number divisible by both (or all) numbers: 2 and 5, here.Knowing that all numbers divisible by 2 have a 0, 2, 4, 6, or 8 in the ones place combined with the knowledge that all numbers divisible by 5 end with 0 or 5 (excluding 0 in both cases), we can say the only multiples of each number that are common to both are numbers that end with 0.Another way of analyzing this problem is to say that both 5 and 2 are factors. 10 is clearly a multiple of 5 and 2 because 2(5)=10. Any number divisible by 10 is thus also divisible by 2 and 5. All numbers divisible by 10 end in 0. Thus, a number ends in 0 if and only if it is divisible by 2 and 5.Answer: Common multiples of 2 and 5 end with zero.

12 and its multiples.

The lists of numbers divisible by and not divisible by 600 are both infinite.

you divide the two numbers by what there both divisible by and do that till you can't do it no more

All numbers having the prime factors 2 and 3 are divisible by both 6 and 2. 6, 12, 18 and so on.

There are 166 multiples of 6 in that range. There are 100 multiples of 10 in that range. There are 33 numbers on both lists. 266 - 33 = 233

There are 166 multiples of 6 in that range. There are 100 multiples of 10 in that range. There are 33 numbers on both lists. 266 - 33 = 233

There are 199 multiples of 5 in that range. There are 128 multiples of 7 in that range. There are 28 numbers on both lists. 1000 - 299 = 701

If the GCF of two numbers is 850, both numbers are multiples of 850. Multiples of 850 include 850, 1700, 2250 and so on. The smallest two numbers that have a GCF of 850 are 850 and 1700. But 1700 is divisible by 850. 1700 and 2250 are the next two smallest and are not divisible by each other.