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This is not possible to do. Here's why:

Since 9 is the highest number, it must go on the bottom and be the sum of two lesser numbers.

Those two lesser numbers will add up to 9, obviously.

The sum of 1 through 9 is 45.

45 minus 9, then minus those two numbers equals 27.

This means that the remaining squares sum to 27. Since whats on the top two rows must equal whats on the bottom row, we can determine that the two remaining bottom squares would sum to 27/2 or 13.5. Since this is not a whole number(integer), the problem has no solution.

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Q: Arrange the numbers 1 to 9 in a 3 x 3 box so the bottom number totals the top two?
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