4 times the impact.
The formula is 1/2 mass times velocity squared.
The surface area of the 'sphere' is four times the area of a 'great circle',or (4 pi) times the RADIUS squared.
Force times distance equals work.
Force times distance is called "Work" for the purposes of physics.
2 times pi times the radius squared plus 2 times pi times the radius times the height equals surface area of a cylinder :]
Depends on what you are looking for. At a quick guess, you might be looking for the formula for figuring out the FORCE required for acceleration, or deacceleration. Force = mass * acceleration Force is given in Newtons Mass is given in Kg Acceleration is given in m/second^2 So, if YOU have a mass of 45 Kg, and gravity is 9.8m/sec^2, you are exerting a force of 441 Newtons on the surface you are standing on.
4 times.
Double the speed yeilds double the impact force.
Yes. (1/2 mass x velocity squared)
Pretty sure this is true...let me guess, the drug and alcohol test? I'm taking it too.
YES
At the surface, it is 2.64 times its value at the Earth's surface.
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
The acceleration of gravity at the surface of Mercury is 3.7 m/sec2. The force on a mass on the planet's surface depends on the size of the mass. The magnitude of the force, in newtons, is (3.7) times (the object's mass).
yes a scale reads a force. called the normal force which on a flat surface equals your mass times gravity
Jupiter has approximately that surface gravity.
The force of friction on an object is equal to the coefficient of friction times the force perpendicular to the surface (normal force). When the mass of an object increases, the normal force increases, and the force of friction also increases. However, because the equation does not involve surface area, increasing surface area has no affect on the force of friction.
If the object is moving along a horizontal surface with a constant acceleration,then the net vertical force on it is zero, and the net horizontal force on it is(the pushing force) minus (any kinetic friction force where it rubs the surface).The numerical value of that net force is(the acceleration) times (the object's mass).