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answer is 325 adult tickets were sold ( fmtickets.com )

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Q: At a local theatre adult tickets cost 8 and student tickets cost 5 at a recent show 500 were sold for a total of 3475 how many adult tickets were sold?
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At a local theater adult tickets cost 8 and student tickets cost 5 At a recent show 500 tickets were sold for a total of 3475 How many adult tickets were sold?

a=# of adult tickets, s=# of student tickets 8a+5s=3475 a+s=500 Solve for s in this equation: s=500-a Now substitute 500-a in for s in the equation 8a+5s=3475: 8a+5(500-a)=3475 8a+2500-5a=3475 3a=975 a=325 ans. There were 325 adult tickets sold.


Sold 325 tickets to a game Adult tickets were 5 each and student tickets were 2 each How many of each type of ticket were sold is 995 was made?

Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.


Michelle sold tickets for the basketball gameEach adult costs 3.00 and each student ticket cost 1.50 There were 105 tickets sold for a total of 250.00How many of each type of ticket were sold?

Sounds like a system of equations. X = adult ticket Y = student ticket Change all to pennies for convenience. X + Y = 105 300X + 150Y = 25000 -150(X + Y = 105) - 150X - 150Y = - 15750 300X + 150Y = 25000 -----------------------------------add them 150X = 9250 X = 62 adult tickets ------------------------ Y = 43 student tickets -------------------------- Those two prices added together = $250.50 So, we are a little off. I rounded the adult ticket number, but pieces of tickets can not be sold, so check work.


Admission tickets to a motion pictures theater were priced at 4 for adults and 3 for students If 810 tickets were sold and total recipients were 2853 how many of each type of ticket were sold?

x=adult y=student x+y=810 4x+3y=2853 3240-y=2853 y=387 x=423 check: 4*423=1692 3*387=1161 add together 2853 423 adult tickets 387 student tickets


The attendance at a ball game was 400 people Student tickets are 2 and Adult tickets are 3 If 1050 was collected in ticket sales how many of each type of ticket were sold?

s- student, price of ticket is $2 a- adult, price for ticket i s$ 3 2*s money collected from students 3*s money collected from adults if a+s=400 and 3*a+2*s=1050 we have system of linear equations so a=400-s substitute in second equation a with 400-s then 3*(400-s) +2*s=1050 1200-3*s +2s=1050 1200 - s = 1050 -1200 -1200 -s = - 150 s=150 if s=150 then a=400-s so a=400-150, thus a=250 At the game sold 250 adult tickets and 150 student tickets

Related questions

19 At a local theater adult tickets cost 8 and student tickets cost 5 At a recent show 500 tickets were sold for a total of 3475 How many adult tickets were sold?

Adults: 325 Student: 175


Mimi had 174 to buy tickets to a concert The adult tickets cost 10.50 and the student tickets cost 7.50 She bought 4 more student tickets than adult tickets How many student tickets did she buy?

12 student tickets


Mimi had 174 to buy tickets to a concert The adult tickets cost 10.50 and the student tickets cost 7.50 She bought 4 more student tickets than adult tickets How many adult tickets did she buy?

8 Adult tickets


The tickets for a movie were 10 for an adult and 4 for a student. Find the total income from the sale of 87 adult tickets and 135 student tickets?

870 + 540 = 1410


At a local theater adult tickets cost 8 and student tickets cost 5 At a recent show 500 tickets were sold for a total of 3475 How many adult tickets were sold?

a=# of adult tickets, s=# of student tickets 8a+5s=3475 a+s=500 Solve for s in this equation: s=500-a Now substitute 500-a in for s in the equation 8a+5s=3475: 8a+5(500-a)=3475 8a+2500-5a=3475 3a=975 a=325 ans. There were 325 adult tickets sold.


A total of tickets were sold for the school play There were more student tickets sold than adult tickets How many adult tickets were sold?

Your question lacks the info necessary to answer it.How many tickets were sold in total?What percentage of either student or adult tickets sales were sold?Your question cannot be answered as written.


Marc sold 461 tickets for the school play Student tickets cost 3 and adult tickets cost 4 Marc's sales totaled 1624 How many adult tickets and how many student tickets did Marc sell?

220 Tickets at 3 = 660 241 Tickets at 4 = 964 ---------------------------- 461 1624


A total of 725 tickets were sold for the school play There were 75 more student tickets sold than adult tickets How many adult tickets were sold?

325 Tickets sold to adults 400 tickets sold to students


A total of 700 tickets were sold for the school play There were 50 more student tickets sold than adult tickets How many adult tickets were sold?

700/2 = 350350 - 25 = 325325 adult tickets700 - 325 = 375375 kids tickets


Adult tickets for a game cost 4 each and student tickets cost 2 each total of 920 tickets worth 2446 were sold how many student tickets were sold?

If A is number of adult tickets, and B is number of student tickets, we get a system of two equations for two unknowns: 4A+2B=2446 A+B=920 By solving this system, we obtain B=617


Sold 325 tickets to a game Adult tickets were 5 each and student tickets were 2 each How many of each type of ticket were sold is 995 was made?

Let A be the number of adult tickets sold. As 325 tickets in total were sold, the number sold to students was 325 - A. The income from the sale of adult tickets = A x 5 = 5A The income from the sale of student tickets = (325 - A) x 2 = 650 - 2A Total Income = 995 = 5A + 650 - 2A = 3A + 650 3A = 995 - 650 = 345 A = 115, therefore S = 325 - 115 = 210. 115 Adult tickets were sold and 210 Student tickets.


Adult ticket are 5 and student tickets are 3 ben collected 180 for the 50 tickets he sold how many adult tickets were sold how many student tickets were sold?

A + S = 50 ===> S = 50 - A5A + 3S = 1805A + 3(50 - A) = 1805A + 150 - 3A = 1802A = 30[ A = 15 ][ S = 35 ]=====================Check:5(15) + 3(35) = 75 + 105 = 180 yay!