$90If the area of the garden is 50 ft2, then the area is represented by the formula50 = l * wIf the length is twice the width, then l = 2w, and50 = 2w * w ===> 50 = 2w2Solving for w, we getw = 5Now the perimeter of the fencing is 2w + 2(2w) = 6w, and with w = 5P = 6(5) = 30.If the fencing costs $3/ft, then we have$3/ft * 30 ft = $90
A = area, L = length, W = width A = LW L = 2W A = (2W)W = 2W2 2W2 = 50 W = 5 ft
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area
68m
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
$90If the area of the garden is 50 ft2, then the area is represented by the formula50 = l * wIf the length is twice the width, then l = 2w, and50 = 2w * w ===> 50 = 2w2Solving for w, we getw = 5Now the perimeter of the fencing is 2w + 2(2w) = 6w, and with w = 5P = 6(5) = 30.If the fencing costs $3/ft, then we have$3/ft * 30 ft = $90
the length of a rectangular garden is 2 feet longer than 3 times it's width .if the perimeter of the garden is 100 feet find the width and length of the garden
A = area, L = length, W = width A = LW L = 2W A = (2W)W = 2W2 2W2 = 50 W = 5 ft
Only one way to find out: measure the width and the length of the garden, add them together and multiply by two which gives the perimeter of the rectangular garden.
the length of a rectangular garden is 12 meters and the width is 7 meters. What is the area
If the garden is rectangular shape then the perimeter (total length of all sides) would be 80 feet. If you divide that by3 you would have 26.667 yards. So it sounds as though it would require at least more 2 yards of fencing.
Let the length be 2x and the width be x: length*width = area 2x*x = 50 2x2 = 50 x2 = 25 x = 5 feet
28
14 cm
68m
832 yards
length = 22 meters and width = 6 meters