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Bob invests part of 13000 at 3 perc simple annual interest and the rest at 2 perc simple annual interest If his total yearly interest from both accounts was 340 find the amount invested at each rate.?
Mellick66
Suppose he invested x at 3%.
Then x*3/100 + (13000-x)*2/100 = 340
=> 3x + 26000 - 2x = 34000
=> x = 34000 - 26000 = 8000.
So 8000 at the higher rate and 5000 at the lower.
Suppose he invested x at 3%.
Then x*3/100 + (13000-x)*2/100 = 340
=> 3x + 26000 - 2x = 34000
=> x = 34000 - 26000 = 8000.
So 8000 at the higher rate and 5000 at the lower.
Suppose he invested x at 3%.
Then x*3/100 + (13000-x)*2/100 = 340
=> 3x + 26000 - 2x = 34000
=> x = 34000 - 26000 = 8000.
So 8000 at the higher rate and 5000 at the lower.
Suppose he invested x at 3%.
Then x*3/100 + (13000-x)*2/100 = 340
=> 3x + 26000 - 2x = 34000
=> x = 34000 - 26000 = 8000.
So 8000 at the higher rate and 5000 at the lower.
Wiki User
∙ 9y ago
Wiki User
∙ 9y agoSuppose he invested x at 3%.
Then x*3/100 + (13000-x)*2/100 = 340
=> 3x + 26000 - 2x = 34000
=> x = 34000 - 26000 = 8000.
So 8000 at the higher rate and 5000 at the lower.
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