2C3H8 + 10O2 = 6CO2 + 8H2O
H2 - hydrogen.
The anwer is 2 (C2H6) + 7(O2) =4 (CO2) + 6 ( H2O) left side : C=4 , H= 12, O=14 right side : C=4 , H= 12, O=14 so they are balanced.
Co can mean joint, together or the similar; however it doesn't always mean equal. For example: co-owners in a business are both owners. However, they do not necessarily have to have equal ownership.
Co-interior angles are not congruent. The only case in which they would be is if the transversal was perpendicular to the two parallel lines.
Yes.
c4 +H10 --->CO+ H2O
No. The correct one is CO + H2O ----> HCOOH (Formic acid)
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.
It can be. When the liquid petroleum gas (LPG) is incompletely oxidized due to a reduced oxygen level, CO (carbon monoxide) as well as CO2 (carbon dioxide) is produced. LPG gas is mostly propane and/or butane. For propane, the comparative reactions are: (excess O2) C3H8 + 5 O2 → 3 CO2 + 4 H2O + heat (insufficient O2) C3H8 + 4.5 O2 → 2 CO2 + CO + 4 H2O + heat
The equation is H2CO3 --> H2O + CO2
H2 - hydrogen.
its balanced
Keq = [H2O][CO] [H2][CO2]
C + h2o = co + h2
This is an exothermic reaction.
Co + h2o = co + h2
Carbon monoxide is released in the combustion of liquid petroleum gas due to the incomplete oxidation of some fractional components, including propane, when a buildup of exhaust gas reduces the oxygen available to the flame. Almost all of the gas released by properly functioning heaters is carbon dioxide, and heated carbon monoxide may be carried away through a vent or exhaust. For propane, the comparative reactions are: (excess O2) C3H8 + 5 O2 → 3 CO2 + 4 H2O + heat (insufficient O2) C3H8 + 4.5 O2 → 2 CO2 + CO + 4 H2O + heat