No. When 512 is divided by 3 the result is not an integer. It is 170.66666666.
128
hcf(324, 512) = 4 324 = 2² x 3⁴ 512 = 2⁹ hcf = 2² = 4
No. If the last two digits of a number are divisible by 4, then the whole number is divisible by 4. So, 34 is not divisible by 4, therefore 634 is not divisible by 4.
128 (128 times 4 gives 512)
512 is not divisible by 3.
No.
Yes 256 x 2 = 512
No.
No. When 512 is divided by 3 the result is not an integer. It is 170.66666666.
1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024.
Neither of them are prime. 45 is divisible by 5 and 9. 1024 is divisible by 2 and 512.
512/4 = 128
512 × 4 = 2048
128
512/4 = 256/2 = 128
hcf(324, 512) = 4 324 = 2² x 3⁴ 512 = 2⁹ hcf = 2² = 4