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Yes because the given numbers complies with Pythagoras' theorem for a right angle triangle
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What will be the lenght of the diagonal piece of pipe if the lawn is a rectangle 15 feet long and 8 feet wide?
use pythagorean's theorem... 152 + 82 = c2 c = 17 the length of the pipe will be 17 feet long
The hypotenuse of a right triangle with legs of lengths 8 and 15?
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
What is the pythagorean triple of 16-30-34?
8, 15, 17
What is the area of a triangle with a hypotenuse of 17 and height of 15?
The reference to hypotenuse tells you that this is a right triangle, so the Pythagorean theorem applies. You can't figure area until you know both legs of the right triangle. Letting x be unknown side, you can write 15^2 + x^2 = 17^2. Rearranging: x^2 = 17^2 - 15^2. Use a calculator. x turns out to be a whole number. The area of a right triangle is half the product of its sides (picture a rectangle cut in half diagonally). That would be (x*15)/2.
What is the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length?
Using Pythagoras' theorem it is 17 units in length
Can eight fifteen and seventeen represent the sides of a right triangle?
Yes. The hypotenuse is the longest side here, which is 17. Using Pythagorean theorem, 17² must equal the other two sides squared. 17² =289 8²+15² =64+225 =289 Since it satisfies the conditions of the Pythagorean theorem, they can represent the sides of a right triangle.
What will be the lenght of the diagonal piece of pipe if the lawn is a rectangle 15 feet long and 8 feet wide?
use pythagorean's theorem... 152 + 82 = c2 c = 17 the length of the pipe will be 17 feet long
The hypotenuse of a right triangle with legs of lengths 8 and 15?
Let c be the hypotenuse and use the Pythagorean theorem. 8^2 + 15^2 = c^2 64 + 225 = c^2 289 = c^2 17 = c
What is the pythagorean triple of 16-30-34?
8, 15, 17
What combination of integers can be used to generate the pythagorean triple 8 15 17?
x=4 y=1
Is 10 14 17 considered a pythagorean triple?
Nearly but not quite a Pythagorean triple
What is the area of a triangle with a hypotenuse of 17 and height of 15?
The reference to hypotenuse tells you that this is a right triangle, so the Pythagorean theorem applies. You can't figure area until you know both legs of the right triangle. Letting x be unknown side, you can write 15^2 + x^2 = 17^2. Rearranging: x^2 = 17^2 - 15^2. Use a calculator. x turns out to be a whole number. The area of a right triangle is half the product of its sides (picture a rectangle cut in half diagonally). That would be (x*15)/2.
What is the length of the hypotenuse of a right triangle with legs of lengths 8 and 15?
17 units using Pythagoras' theorem
What is the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length?
Using Pythagoras' theorem it is 17 units in length
What is the length of the hypotenuse of a right triangle whose legs are 8 and 15 units in length.?
Using Pythagoras' theorem the length of the hypotenuse is 17 units
A right triangle has a hypotenuse of length 17 and a leg of length 13?
Use Pythagorean Theorem: a2+b2=c2, where a=13 and c=17; so 132+b2=172, perform squaring to get 169+b2=289, then subtract so b2=120, and take the square root so b~10.95
How are Pythagoras' theorem and Fermat's last theorem related?
Pythagoras' theorem proves that if you draw a square on the longest side (the hypotenuse) of a right-angled triangle, its area is the same as the areas of the squares drawn on the two shorter sides, added together. See 'Pythagoras' theorem' under 'Sources and related links' below.Pythagoras' theorem holds for any right-angled triangle. But of special interest to Fermat were right-angled triangles where all the three sides were whole number lengths. These special lengths are known as Pythagorean triples.Here are some Pythagorean triples:-(3,4,5) (5, 12, 13) (7, 24, 25) (8, 15, 17)In each case, the square of each of the smaller numbers is equal to the square of the largest number.Fermat said that if instead of constructing squares (two dimensional figures) on the sides of right-angled triangles, you constructed cubes (three dimensional analogs of squares), or hypercubes (four dimensional analogs) or higher dimensional cube-analogs, there are no equivalents to the Pythagorean triples. In other words, there are no whole number values for 3, 4 or more dimensional analogs of the square.
