Yes, but a parabola, itself, can have only a vertical line of symmetry.
No, a shape is more technically referred to as a polygon. Some examples of polygons include squares and triangles. Polygons cannot have curved sides so therefore a parabola is not a polygon nor a shape. A parabola is a line, it extends in the direction it is going for infinity.
A parabola is not a shape, it is actually a curved line in a coordinate plane. It is shaped like a U turned in any direction. The two basic equations for it are y=a(x-h)2+k or x=a(y-k)2+h.
A parabola is a curved shape that is plotted on the Cartesian plane.
Yes
It is a function because for every point on the horizontal axis, the parabola identified one and only one point in the vertical direction.
No, a shape is more technically referred to as a polygon. Some examples of polygons include squares and triangles. Polygons cannot have curved sides so therefore a parabola is not a polygon nor a shape. A parabola is a line, it extends in the direction it is going for infinity.
The line of symmetry located on a parabola is right down the center. A parabola is a U shape. Depending on the direction of the parabola it either has a x axis of symmetry or y axis of symmetry. You should have two equal sides of the parabola.
A parabola is not a shape, it is actually a curved line in a coordinate plane. It is shaped like a U turned in any direction. The two basic equations for it are y=a(x-h)2+k or x=a(y-k)2+h.
A parabola is a curved shape that is plotted on the Cartesian plane.
Yes
It is a function because for every point on the horizontal axis, the parabola identified one and only one point in the vertical direction.
Trajectory is the path a projectile follows Parabola is the shape of this path
The graph of a quadratic equation is a parabola.
The parabola shape is magnified. If you keep the same scale for the graph, the parabola will look wider, more flattened out.
A parabola can open left, down, right, or left on a graph, if that's what you mean:\
The focus of a parabola is a fixed point that lies on the axis of the parabola "p" units from the vertex. It can be found by the parabola equations in standard form: (x-h)^2=4p(y-k) or (y-k)^2=4p(x-h) depending on the shape of the parabola. The vertex is defined by (h,k). Solve for p and count that many units from the vertex in the direction away from the directrix. (your focus should be inside the curve of your parabola)
parabola