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Yes but only if the denominator is 0 (so the quotient is not defined).

Q: Can have two real numbers if the quotient is not real number?

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Any positive number can be written as a quotient of two positive numbers or a quotient of two negative numbers. Any real number can be written as the quotient of two real numbers.

An Irrational Number..

Irrational number

Quotient is the number you get when dividing two numbers.

If a number can be expressed as the quotient of two numbers (a Ã· b) and b is not zero, then it is a rational number.

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Any positive number can be written as a quotient of two positive numbers or a quotient of two negative numbers. Any real number can be written as the quotient of two real numbers.

No. Not if the second number is zero.

Yes, a rational number is a real number. A rational number is a number that can be written as the quotient of two integers, a/b, where b does not equal 0. Integers are real numbers. The quotient of two real numbers is always a real number. The terms "rational" and "irrational" apply to the real numbers. There is no corresponding concept for any other types of numbers.

A real number is any number so yes it is always a real number * * * * * Except if the second number is 0, in which case the quotient is not defined.

An Irrational Number..

Irrational number

The sign of the quotient will be positive. +A/+B = +C. -A/-B = +C. This assumes B is not zero.

Quotient is the number you get when dividing two numbers.

It can be.

No, because a quotient requires two numbers. Given the two numbers it is quite easy to work out the number of digits in the quotient.

If a number can be expressed as the quotient of two numbers (a Ã· b) and b is not zero, then it is a rational number.

The set of rational numbers is a subset of the set of real numbers. That means that every rational number is a real number, but not every real number is rational. The square root of 2 is an example of a real number that isn't rational; that is, it can't be expressed as the quotient of two integers.