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Q: Can sums all rows equal 15 when using 3 rows of 3 and making the diagonal rows also equal 15 using 1 through 9 only once?

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If the vectors emanting from one corner of the rectangel are called a and b then. (a) + (b) = one diagonal (a) + (-b) = the other diagonal and |(a) + (b)| = |(a) + (-b)| (the absolute value of the diagonal's scalars are equal)

Using Pythagoras' theorem the answer is equal to the square root of 2.

Using Pythagoras' theorem the diagonal of the rectangle is about 29.15 units in length

Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 = 14² ÷ 2 = 98 units²

Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49

Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2

Using Pythagoras the diagonal is 20 times square root of 2

Using Pythagoras' theorem the diagonal is 16 times the square root of 2

Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal

Some charts? Buildings Obtuse triangle - some of them are diagonal.

Using Pythagoras' theorem the length of the diagonal is 15 units

Not always, the diagonal can be figured out using the Pythagorean Theorem (a²+b²=c²). Where the diagonal is the hypotenuse (c). By rearranging the Pythagorean Theorem, you can see that the diagonal of a square is always 1.4 times the side of the square.

If the dimensions are for a rectangle then by using Pythagoras' theorem the diagonal works out as 153.364 units of measurement to 3 decimal places.

Using Pythagoras' theorem the length of the diagonal is 20 feet

Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers

Using Pythagoras' theorem: 425

By using the Pythagoras theory, which is a2 + b2 = C2 A and B being each length and c being the diagonal.

Using Pythagoras's theorem, you will find that the diagonal is sqrt(2) = 1.4142 cm (approx),

The path was marked as a red diagonal line on the map. In chess, bishops move along diagonal lines, always on the same colored square. Cut the square of cloth on a diagonal line to form two triangular bandages.

Adding a diagonal stroke through the equals sign (â‰ ) turns the sum into 704384 is unequal to 7127.

As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in

The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.

If it's the dimensions of a rectangle then by using Pythagoras' theorem its diagonal is 40

It has 170 diagonals by using the diagonal formula

Using the quick method, it is 5√2