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sqrt( 16 - x2 ) = sqrt [ (4 + x) (4 - x) ]
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∙ 12y ago
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What is the square root of 96 simplified to?
16, a square number, is a factor of 96. Divide 96 by 16 and you know have 4 (Square root of 16) times the square root of 6.
What is the simplified radical of 4 over square root of 16?
4 over square root of 16 simplifies to 1 !
What is the square root 16 plus square root 49?
It is: 4+7 = 11
What is the answers of 3 square root of (-48) plus 16?
It is 16 +/- 12*sqrt(3)*i where i is the imaginary square root of -1
What is the square root of 16 to the power of 3 simplified?
Expressed in exponential form, sqrt(16)3 is equal to 162 or sixteen squared.
What is the square root of 96 simplified to?
16, a square number, is a factor of 96. Divide 96 by 16 and you know have 4 (Square root of 16) times the square root of 6.
What is the simplified radical of 4 over square root of 16?
4 over square root of 16 simplifies to 1 !
What is the simplified version of the square root of 16x16?
√(16x16) = √(162), and since the square and square root cancel, the square root of 16x16 is 16.
What is the square root of 16 plus square root of 19?
8.358898
What is the square root of 16 plus the square root of 66?
12.1240384046
What is the square root of 160 simplified?
160/16=10 root 160= root 16 times root 10. root 16= 4 so 4 times root ten is your answer
What is the square root 16 plus square root 49?
It is: 4+7 = 11
How do you simplify the square root of 80?
square root of 80 simplified= 16*5= 4 squared *5
What is the square root of 36 plus 10?
square root of 36 plus 10=6+10 , since square root of 36 =6=16Answer : 16
What is the answers of 3 square root of (-48) plus 16?
It is 16 +/- 12*sqrt(3)*i where i is the imaginary square root of -1
Square root of 32 in simplified form?
√32 = √(16x2) = √16 √2 = 4 √2
Simplify the square root of 243?
Are you familiar with the concept of the square root of -1?This is represented by iFor the square root of 243 we can get i involved and say wer are looking for the square root ot [256 - 13(i2)]This can be simplified to [+/-16 - √13(i)]
