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Can you Show 1 over sinx cosx - cosx over sinx equals tanx?
Someboredperson
From the Pythagorean identity, sin2x = 1-cos2x.
LHS = 1/(sinx cosx) - cosx/sinx
LHS = 1/(sinx cosx) - (cosx/sinx)(cosx/cosx)
LHS = 1/(sinx cosx) - cos2x/(sinx cosx)
LHS = (1- cos2x)/(sinx cosx)
LHS = sin2x /(sinx cosx) [from Pythagorean identity]
LHS = sin2x /(sinx cosx)
LHS = sinx/cosx
LHS = tanx [by definition]
RHS = tanx
LHS = RHS and so the identity is proven.
Q.E.D.
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∙ 13y ago
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Prove this identity 1 plus cosx divide by sinx equals sinx divide by 1-cosx?
2
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Prove this identity 1 plus cosx divide by sinx equals sinx divide by 1-cosx?
2
How do you solve 1 minus cosx divided by sinx plus sinx divided by 1 minus cosx to get 2cscx?
(1-cosx)/sinx + sinx/(1- cosx) = [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)] = [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)] = [2 - 2cosx]/[sinx*(1-cosx)] = [2*(1-cosx)]/[sinx*(1-cosx)] = 2/sinx = 2cosecx
How do you simplify cosx plus sinx tanx?
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How do you express the term 1-csc squared x all over sin x cot x to cos x?
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x = 3pi/4
How do you prove the following equation the quantity of sin theta divided by 1 minus cos theta minus the quantity 1 plus cos theta divided by sin theta equals 0?
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How do you solve csc x-sin x equals cos x cot x?
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Cos x plus sin x equals 0?
cosx + sinx = 0 when sinx = -cosx. By dividing both sides by cosx you get: sinx/cosx = -1 tanx = -1 The values where tanx = -1 are 3pi/4, 7pi/4, etc. Those are equivalent to 135 degrees, 315 degrees, etc.
Parenthesis 1 plus tanx end parenthesis divided by sinx equals cscx plus secx?
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What is sin 3x in terms of sin x?
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