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Q: Can you Using four fours make the answer of nineteen?

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fourteen take away four and then add a four and times by (2 times 4)

4! - 44/4 = 24 - 11 = 13

A solution to the four fours problem for the number 33 is: 33 = (4-.4)/.4+4!

Google "Four Fours" and you will find a number of solutions, presented more comprehensively than we can.

4! * 4/(4+4)

(4+4)/4 + 4

As a solution to the four fours problem (using the number four no more than four times to come up with the solution, 31 is equal to (4!+4)/4+4!

4 × ((4 ÷ 4) + 4)=20

There are several ways of making 10 using four fours. Amongst them are the following: (44 - 4)/4 = 10 44 / 4.4 = 10 4 + sqrt(4) + sqrt(4) + sqrt(4) = 10

(4 x 4 + 4) ÷ 4

4! - (4 x 4) - 4

4+4-(4/4)=7

11 = 4/.4 + 4/4

4 + 4 + (4/4) = 9

508 = 44 x sqrt(4) - 4

4*4+4/4 = 17

(4/4)*4!/4 = 6

4! + sqrt(4) - (4/4) = 25

it is not posible *Ahem*. 4*4+4/sqrt(4)

yes by taking out one then u will get 4 like 5-1=4 like that simple as that.....loxl..hehehe..its so funny

To make 5 using only four 4's, you can either do: 4/4+square root of 4+square root of 4=5 OR: (4x4+4)/4=5 Hope that helped!!

4x4+4-square root of 4=18

(44 - 4)/4 x 4/4

If you are allowd to use .4 and factorial, the answer will be 4! - (.4 - 4!) / .4

I am not aware of a solution using the four basic operations of arithmetic, but otherwise: 129 = [(4^4)/sqrt(4)] + sqrt(sqrt(sqrt(sqrt...(sqrt(4))...))) * * * * * * * * * * * * No matter how many times you square root it, it will not equal 1 To the OP. I have spend a lot of time on this one. Just wanting to make sure that the correct number is 129 and you are sure you are using only 4 fours. It would work out great if using 5 fours. If you made a mistake, correct it and I'll check back. In the mean time, I'll continue thinking about a solution for 4 fours and 129.

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