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First find the length of the base: base = area times 2 divided by height base = 12x2/4 = 6 inches An isosceles triangle can be considered as being two right angled triangles joined together. So by halving the length of the base we can use Pythagoras' Theorem to find the hypotenuse: base2+height2 = hypotenuse2 32+42 = 25 square inches. Square root of 25 = 5 inches Therefore the isosceles triangle has two equal sides of V inches and a base of VI inches.

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Q: Can you find the dimensions of an isosceles triangle with an area of XII square inches and a height of IV inches showing details of your work?
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