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From 1 to 12 the numbers add to 78.

If each of the 3 parts has to be equal then they must add up to 26 (a third of 78).

I think the closest you will be able to get is 25, 26, 27.

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Q: Can you make an algorithm that will divide a clock face into three parts so that the sum of the numbers in each part is equal to the other two parts?
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Related questions

Can you use one straight line to divide the numbers on a clock face so that the sums of the numbers on the two sides of the lines are equal?

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