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Q: Can you test the multiples of 9 using the divisibility trick for 9?

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you can't

1, 2, 3, 5, 6, 10, 15, 30

To test divisibility for 20, you need to use the tests for divisibility by 4 and 5.The test for divisibility by 4 is that the last 2 digits of the number, given as a 2-digit number, are divisible by 4.Example for 4:We are testing the number 11042.42/4 = 10.5 which is not a whole number. Therefore 11042 is not divisible by 4.The test for divisibility by 5 is that the last digit of the number is either 5 or 0.

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all even numbers

Every number has a test for divisibility. The issue is that the tests get more complicated as the divisor increases. For primes up to 50, see either of the attached links.

If the number is also divisible by 2 and 3

The tricks of passing a drug test is abstaining from their use. The other trick is going for the drug test 3 months after using a particular drug.

It is divisibility by 3 and divisibility by 5.Divisibility by 3: the digital root of an integer is obtained by adding together all the digits in the integer, with the process repeated if required. If the final result is 3, 6 or 9, then the integer is divisible by 3.Divisibility by 5: the integer ends in 0 or 5.

A number is divisible by 6 if the number is divisible by 2 AND 3.

Divisibility test for 3 : the sum of digits of the given number must be a multiple of 3 Divisibility test for 4 : the number formed by last 2 digits must be a multiple of 4.

No, you can't.

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