In mathematics, a quadratic equation is a polynomial equation of the second degree. The general form is : where a≠ 0. (For if a = 0, the equation becomes a linear equation.) The letters a, b, and c are called coefficients: the quadratic coefficient a is the coefficient of x2, the linear coefficient b is the coefficient of x, and c is the constant coefficient, also called the free term or constant term. Quadratic equations are called quadratic because quadratus is Latin for "square"; in the leading term the variable is squared. A quadratic equation with real or complex coefficients has two (not necessarily distinct) solutions, called roots, which may or may not be real, given by the quadratic formula: : where the symbol "±" indicates that both : and are solutions.

x^2-3x-28=0...................

the highest exponent of quadratic equation is 2 good luck on NovaNet peoples

Quadratic equations are called quadratic because quadratus is Latin for "square"; in the leading term the variable is squared.

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Quadratic equations are called quadratic because quadratus is Latin for ''square'';in the leading term the variable is squared. also...it is form of ax^2+bx+c=0

The answer depends on the what the leading coefficient is of!

what is the leading coefficient -3x+8

It gets reflected in the x-axis.

It is the coefficient of the highest power of the variable in an expression.

It is the number (coefficient) that belongs to the variable of the highest degree in a polynomial.

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Leading coefficient: Negative. Order: Any even integer.

x the literal coefficient is the letter tagging along with the number coefficient (the number coefficient is 5, here). number coefficient is also sometimes called leading coefficient. literal coefficient is the variable (which is always a letter: English or latin).

For an expression/equation such as this example, -12x^4-8x^2-7, the terms would be as follows: Term 1: -12x^4 Term 2: -8x^2 Term 3: -7 This particular equation has 3 terms, 3 coefficients, but only 1 leading coefficient. These are as follows also: Coefficient 1: -12 Coefficient 2: -8 Coefficient 3: -7 And the last one: Leading Coefficient: -12 Generally the answers are written in descending order according to their exponential power above the variable, which in this case is "x". This means the greater the power of "x", the sooner it will be written down. X^4 is first, x^2 is next, and x^0 is last. Note: x^0 always equals 1.

In other words, the zeroes of -x2 - 7x - 12.First, multiply by -1: x2 + 7x + 12.The new leading coefficient is 1, so the factors take the form (x + _)(x + _), where the two blanked-out numbers add up to 7 and multiply to 12.It's easier to try factoring 12 and adding the factors:1 + 12 = 132 + 6 = 83 + 4 = 7That last one shows us that the factors are (x + 3)(x + 4), and the zeroes are -3 and -4.

Well, that depends on what you mean "solve by factoring." For any quadratic equation, it is possible to factor the quadratic, and then the roots can be recovered from the factors. So in the very weak sense that every quadratic can be solved by a method that involves getting the factors and recovering the roots from them, all quadratic equations can be solved by factoring. However, in most cases, the only way of factoring the quadratic in the first place is to first find out what its roots are, and then use the roots to factor the quadratic (any quadratic polynomial can be factored as k(x - r)(x - s), where k is the leading coefficient of the polynomial and r and s are its two roots), in which case trying to recover the roots from the factors is redundant (since you had to know what the roots were to get the factors in the first place). So to really count as solving by factoring, it makes sense to require that the solution method obtains the factors by means that _don't_ require already knowing the roots of the polynomial. And in this sense, most quadratic equations are not solvable through factoring.

Anywhere. Provided it is not zero, and number p can be the leading coefficient of a polynomial. And any number q can be the constant term.

The leading coefficient doesn't come into play unless certain exponent criteria are matched. I believe that to calculate where the horizontal asymptote is you need to concern yourself with the highest exponent and where it is located ie, the horizontal asymptote for y=(3t^2+5t)/(4t^2-3) is y=3/4

The general form of a quadratic is "y = ax2 + bx + c". For graphing, the leading coefficient "a" indicates how "fat" or how "skinny" the parabola will be.For | a | > 1 (such as a = 3 or a = -4), the parabola will be "skinny", because it grows more quickly (three times as fast or four times as fast, respectively, in the case of our sample values of a). For| a | a = 1/3 or a = -1/4 ), the parabola will be "fat", because it grows more slowly (one-third as fast or one-fourth as fast, respectively, in the examples). Also, if a is negative, then the parabola is upside-down.

find a greatest common factor or GCFin factoring a trinomial with a leading coefficient other than 1 the first step is to look for a COMMON factor in each term

Assuming that a is the leading coefficient of the equation of the parabola, changing it from positive to negative will reflect the parabola along a horizontal line through its minimum - which will then become its maximum.

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