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Evaluate the function at the first number in the pair. If the answer is not equal to the second value, then the ordered pair cannot be in the function.
It could be a function or a linear expression.
You could put the equation in slope-intercept form or in parent linear function or even make a table of values.
One. To be a (non-trivial) linear programming problem both the objective function and the constraints must be linear. If there were no constraints then the objective function could be made arbitrarily large or arbitrarily small. (Think of a line in two-space.) By adding one constraint the objective function's value can be limited to a finite value.
Yes.You could also state that the circumference is directly proportional to the radius. The proportionality constant is (2 pi).
Evaluate the function at the first number in the pair. If the answer is not equal to the second value, then the ordered pair cannot be in the function.
no it can't because linear fuctions are straight
It could be a function or a linear expression.
You didn't show the Ordered Pairs so there is no way this question could be answered.
A set of points forming a straight line.
You could put the equation in slope-intercept form or in parent linear function or even make a table of values.
It is a function of the form D = ax + b where a and b are some constants and x is a variable which is linearly related to the demand. x could be the price of the goods in question, or be the price of a complementary good, a substitute, or it could be income, or time. Also, a linear relationship does not mean a causal relationship.
A non-linear graph. It could be a polynomial (of a degree greater than 1), a power function, a logarithmic or trigonometric graph. In fact any mathematical function other than a linear equation.
(2, 4)
One. To be a (non-trivial) linear programming problem both the objective function and the constraints must be linear. If there were no constraints then the objective function could be made arbitrarily large or arbitrarily small. (Think of a line in two-space.) By adding one constraint the objective function's value can be limited to a finite value.
Yes.You could also state that the circumference is directly proportional to the radius. The proportionality constant is (2 pi).
No, it could be a constant.