CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
ATP plus H2O release energy (endergonic reaction) and P. Now, this P plus ADP becomes ATP (exergonic reaction). It's a cyclic process. It starts all over again at ATP plus H2O..
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
Na+ and Cl- are spectator ions.
2h2s + so2 - 2h20 + 3s
It's a simple acid-base reaction, your acid being your 2HCl and your base being CuO. Acid-base reactions form water, leaving behind a salt (CuCl2).
cuo
CuO + H2 ------> Cu + H2O. You shouldn't say "plus" for the reactions, it has to be the arrow as the arrow symbolises lots of complicated reactions, making it different to adding them together.
CuO + 2HCl --> CuCl2 + H2O This equation is a double displacement; because Cu (Copper) has pushed out O (oxygen), so that Cu can be with Cl (chlorine). Also, H (Hydrogen) has pushed out Cl to be with O. Both elements have pushed out their partner, therefore a double displacement.
CuCO3 + H2SO4 -> CuSO4 + H2O + CO2 copper(II) carbonate + sulphuric acid -> copper(II) sulphate water + carbon dioxide
CuO + 2HCl --> CuCl2 + H2O
you obtain Cu from CuO only by reducing with hydrogen or carbon monooxide: CuO + H2 → Cu + H2O
CuO + H2SO4 --> CuSO4 + H2O
The product is copper ii chloride alongwith water, CuO + 2HCl = CuCl2 + H2O
Cu(OH)2 (s) -> CuO(s) + H2O(l)
Cu(OH)2 --> CuO + H2O
CuO + H2 ----> Cu + H2O