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In a calculater or by hand do 295/8 OR

by using the divisibility rule of 8

if the last 3 digits are divisible by 8, so is the entire number. So you would still do 295/8 but now you know why.

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Q: Determine whether 295 is divisible by 8?
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Determine whether 2345804 is divisible by 8 or not?

It is not.


Is 2295 divisible by 8?

Well the rule for disibility of 8 is if the last 3 digits are divisible by 8, so is the entire number. So 295/8 is a decimal...so 2295 is not divisible by 8


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To find out whether a no. is divisible by 7, we must: a) separate the units place: eg. 84 = 8 4 b) then double the no. in units place 4 x 2 = 8 c) subtract it from the no. formed by the remaining digits 8- 8 = 0 Then if the obtained no. is divisible by 7 (0= 7x0) , then the original no. is also divisible. ( 12 x 7 = 84 )


Is 1218 divisible by 3?

Yes, it is. Your answer is 406. You can determine whether a number is divisible by 3 by adding the digits. If the sum of the digits (in the above, 1+2+1+8 = 12) equals 3, the number is divisible by 3.


How can you use the concepts even and odd to determine whether a number is divisible by 2?

If the last digit is 0, 2, 4, 6, 8, then it is divisible by 2. You can just use a calculator though.


How do you know if 54132 is divisible by 6?

To determine if a number is divisible by 6, it must be divisible by both 2 and 3. To determine if a number is divisible by 2, it should be even - in other words, it should end with 0, 2, 4, 6, or 8. To determine if a number is divisible by 3, the sum of its digits should be divisible by 3. 54,132 is an even number, so it is divisible by 2. 5 + 4 + 1 + 3 + 2 = 15, which is divisible by 3, so 54,132 is divisible by 3. Since 54,132 is divisible by both 2 and 3, it is divisible by 6.


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How about: 960


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0.0271


What numbers are divisible by 3 and 8?

Lots and lots of them are. But a good way to determine which ones are is to multiply 3 x 8, which = 24. Then you can multiply 24 x 3 or 24 x 8, and then each of those answers will be divisible by 3 and by 8.You can then multiply those numbers by 3 and/or 8, which will also be divisible by 3 and 8, and on and on....24 and any multiples, plus others...