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Differential co-efficient of log tan x is?

Updated: 4/28/2022
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y = ln(tan(x)) u = tanx y =ln(u) dy/du = 1/u du/dx = sec2(x) dy/dx = dy/du * du/dx = sec2(x)/tan(x)

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Q: Differential co-efficient of log tan x is?
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What is 525677.42742534 to the 85 power?

Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":x = 525677.4274253485log x = log 525677.4274253485Now use a standard property of logarithms:log x = 85 log 525677.42742534log x = (85)(5.72071932882537)log x = 486.261142950157So, the result is approximately 10486. To get the coefficient more accurately:x = 10486.261142950157x = 10486 + 0.261142950157x = 100.26114295015710486x = 1.82449614534211 x 10486


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