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Divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 4?
Wiki User
∙ 16y ago
One part is 63.6 and the other part is 120.4 Let x be one part and y be the other part. (1/3)X = (1/7)Y + 4 ... one third of one part can exceed one-seventh of the other part by 4. X + Y = 184 So you have two equations and two unknowns: X + Y = 184 (1/3)X - (1/7)Y = 4 After rerranging and solving the simlutaneous equations, you get X = 63.6 and Y = 120.4
Wiki User
∙ 16y ago
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Divide 184 into two parts such that one third of one part may exceed one-seventh of the other part by eight?
72 + 112 = 184 24 - 16 = 8
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