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Q: Does 38 have a odd number of different factors?

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Square numbers, like 49, have an odd number of factors.

38 is an even number

If you must keep the "38" as is and just place the 6 before & after the 38, there is no odd number. If you can move the 3 & 8, then the largest odd number would be 863.

The number of odd numbers between 38 and n = int[abs(n - 38)/2]

The factors for the number 38 would be 1,2 and 19. This is a math problem.

Odd. It's 165.

37 is.

even.

even

"Two consecutive numbers" implies that these are whole numbers. Consecutive whole numbers have different parity - that is to say that one is odd and the other even, which means that their sum must be odd. Since 38 is even the problem has no solution.

Proper factors are factors of the number except the number itself. So, with that said, the proper factors of 38 are 1, 2, and 19.

Eliminate the even numbers. Eliminate the odd numbers with more than two factors. 41 is left.

The factors of 38: 1, 2, 19, 38

The factors of 38 are: 1, 2, 19, 38.

The larger number is 20.

Since the greater number 57 is an odd number, then the other number must be 38 which is an even number, smaller than 57.

19 and 38

1,2,19,38

Odd - as it is not dividable by 2 36 is even 38 is even

38 is 2 x 19

38 is an even number so it is divisible by 2. 38 = 2*19 19 is a prime so there are no further factors.

It has more than two factors.

Any of its factors including itself

38 of them.

Yes, you can write 38 as a product of prime factors. Since it is an even number, you can start by dividing 38 by 2. Your answer is 19. Since 2 and 19 are prime numbers, you are done. Prime factorization of 38 is: 2 X 19 = 38