no, unless there is more to the equation
6 - 2 + 2 = 6 (subtracting two and then adding it again creates a negation of both, leaving the original value).
Any value of x! Multiplication is commutative, that is, the order of multiplication doesn't matter, so 2x3=3x2, 23x45=45x23, and so on. Hence, 2 times x and x times 2 are the same. Therefore, it doesn't matter what x is!
The value of x can be determined by subtracting 6 from 9.
The RULES for subtraction do not depend on the signs of the numbers. A - B means the value of A (+ or -) minus the value of B(+ or -). So if A is -1 and B is -2 you have (-1) - (-2). Subtracting a minus is a plus (like taking away a debt). So: (-1)+2 or -1+2 = 1. Think of positives as dollars in your hand, and minuses as bills in your hand you have to pay. If someone takes away a bill, you are better off. Similarly for distances. So it does matter - you must do it properly.
y
It would equal to zero.
Subtracting a negative integer is the same as adding its absolute value.
equivulant exchange In order to get something of equal value must give somethin equal value
Yes, as no matter how many zeros exist at the end, if no value is at the end that is > 0, then it is equal.
6 - 2 + 2 = 6 (subtracting two and then adding it again creates a negation of both, leaving the original value).
Any value of x! Multiplication is commutative, that is, the order of multiplication doesn't matter, so 2x3=3x2, 23x45=45x23, and so on. Hence, 2 times x and x times 2 are the same. Therefore, it doesn't matter what x is!
Vertical.
Range
0
The range.
The value of x can be determined by subtracting 6 from 9.
Zero. The absolute value |n| is positive for any real number. Subtracting it from itself is zero.