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Q: Does the altitude to the base of an isosceles triangle bisect the vertex angle?
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Can the altitude from the vertex angle of an isosceles triangle be the median?

If the triangle is really isosceles, and it's not lying on one of the equal sides, then the altitude is always a median.


Do the medians of a triangle bisect the internal angles?

Not always. 1. The median to the base of an isosceles triangle bisects the vertex angle. 2. When the triangle is an equilateral triangle, then the medians bisect the interior angles of the triangle.


Does the angle bisector in a triangle bisect the opposite side?

Not necessarily. The only time that the angle bisector would bisect the opposite side is if you were bisecting the vertex angle of an isosceles triangle.


When is a median and an altitude the same segment?

In an isosceles or equilateral triangle, when from the vertex that is different from the others.


Is the altitude of a triangle is a segment whose endpoints are a vertex of a triangle and the midpoints of the side opposite the vertex?

Yes but only if it's an equilateral or an isosceles triangle otherwise it's the vertical perpendicular height


How is an isosceles trapezoid related to an isoceles triangle?

If the sloped sides of an isosceles trapezium are extended to a vertex, you would get an isosceles triangle.If the sloped sides of an isosceles trapezium are extended to a vertex, you would get an isosceles triangle.If the sloped sides of an isosceles trapezium are extended to a vertex, you would get an isosceles triangle.If the sloped sides of an isosceles trapezium are extended to a vertex, you would get an isosceles triangle.


In an isosceles triangle does the median to the base bisect the vertex angle?

In the diagram, ABC is an isoscels triangle with the congruent sides and , and is the median drawn to the base . We know that ∠A ≅ ∠C, because the base angles of an isosceles triangle are congruent; we also know that ≅ , by definition of an isosceles triangle. A median of a triangle is a line segment drawn from a vertex to the midpoint of the opposite side. That means ≅ . This proves that ΔABD ≅ ΔCBD. Since corresponding parts of congruent triangles are congruent, that means ∠ABD≅ ∠CBD. Since the median is the common side of these adjacent angles, in fact bisects the vertex angle of the isosceles triangle.


What is the angle of an isosceles triangle?

The two angles that are not the isosceles vertex are equal.


Does isosceles triangle have a vertex angle?

yes they do


A perpendicular segment with one endpoint at a vertex and the other endpoint on the side opposite that vertex?

Altitude: The altitude of a triangle is a perpendicular segment that connects a vertex and its opposite side. Let's construct the altitude of a triangle using a new triangle.


How would you construct an isosceles triangle if only given the vertex angle and the radius of the circumscribed circle?

You have an isosceles triangle, and a circle that is drawn around it. You know the vertex angle of the isosceles triangle, and you know the radius of the circle. If you use a compass and draw the circle according to its radius, you can begin your construction. First, draw a bisecting cord vertically down the middle. This bisects the circle, and it will also bisect your isosceles triangle. At the top of this cord will be the vertex of your isosceles triangle. Now is the time to work with the angle of the vertex. Take the given angle and divide it in two. Then take that resulting angle and, using your protractor, mark the angle from the point at the top of the cord you drew. Then draw in a line segment from the "vertex point" and extend it until it intersects the circle. This new cord represents one side of the isosceles triangle you wished to construct. Repeat the process on the other side of the vertical line you bisected the circle with. Lastly, draw in a line segment between the points where the two sides of your triangle intersect the circle, and that will be the base of your isosceles triangle.


The equal angles of an isosceles triangle?

To find the equal angels, base angles, of an isosceles triangle and you know the vertex angle, 180-vertex angle and then divide by two.