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Q: Domain of x squared minus 4 x?

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(x - 5)(x + 4)

(x+4)(x-7)

D = {x [element of reals]}R = {y [element of reals]|y >= 4}

(x + 2)(x - 4)

4

The domain is what you choose it to be. You could, for example, choose the domain to be [3, 6.5] If the domain is the real numbers, the range is [-12.25, âˆž).

x = ? 42 = x squared minus x

x(x + 3)(x - 4)

1/x4

2

X2 - 4= (x + 2)(x - 2)===========

(x-1)(x-4)

It is the difference of squares. (x-4) and (x+4) <--- answer

x2 - 4= (x+2) (x-2)

4(x - 1)(x + 1)

3x2 - 11x - 4 = (x-4)(3 x + 1)

It is not clear what you want to solve for.

It is x^2 -x -12 is (x+3)(x-4) when factored

x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).

x2-4x-165 = (x-15)(x+11) when factored

-22 - -22

x^2 - y^2 - 4 is in its simplest form.

By factoring I get x-3 divided by x+3

(x - 4)(3x + 5)

x2-5x-36 = (x-9)(x+4) when factored