Study guides

Q: What makes a number divisible by 9?

Write your answer...

Submit

Related questions

Every number is divisible by 9 but the answer wont necessarily be a whole number.

A prime number is not divisible by any numbers except 1 and itself. A composite number is divisible by other numbers. 9 is divisible by 3, so it is a composite number.

If a number is not divisible by 3 then it is not divisible by 9.

Yes, every number that's divisible by 9 is divisible by 3

Yes, any number divisible by 9 is also divisible by 3.

No - any number divisible by 9 will have the sum of its digits divisible by 9.

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

9 is divisible by 1, 3 and 9.

A number is divisible by 9 of its digits add up to a multiple of 9.

yes, you know that because if you add the digits together and that number is divisible by 9, then that large number is divisible by 9. 3+4+2 is 9, which is divisible by 9. conclusion 342 is divisible by 9.

None, because 9 is divisible by 3.

1258 isn't divisible by 9. 1251 and 1260 are. The digits of numbers that are divisible by 9 add up to a multiple of 9. If you were to stick a 2 in there somewhere, the result would be divisible by 9.

If the digits of a number add up to a multiple of 9, the whole number is divisible by 9.

The formal answer is that 18 goes into the number without remainder. A simple test for divisibility by 18 is as follows: (a) the number must be even. (b) the sum of all the digits of the number must be divisible by 9. (a) ensures the number is divisible by 2 and (b) that it is divisible by 9. So, together they ensure divisibility by 2*9 = 18. Note that (b) only works with 3 and 9.

There is only one number in 3206 and that is 3206. And that, is not divisible by 9.

Any even number divisible by 9, if the sum of the digits is divisible by 9. If it's an even number divisible by 9, it's divisible by 18.

There are many numbers between 500 and 1000 divisible by 3 and 9. Any number divisible by 9 is divisible by 3. How about 900?

the rule for divisibility by 9 is that the sum of all digits of the number should should be divisible by 9. So, 3+9+0+6+5= 23. To make is divisible by 9, we think of 27 (as the next number divisible by 9) and that means if we add 4 to any digit of the number, it will be divisible. 39069/9=4341

Not always because 33 is divisible by 3 but not by 9

Yes it is. In order for it to be divisible by 9, the sum of the digits in the number must also be divisible by 9. In this case - the sum of the digits is 27.

a number is divisible by 9 if the sum of the digits is divisible by 9.

A number is divisible by 9 if the sum of its digits is divisible by 9. Thus, the number 99999 is divisible by 9 (the sum of its digits is 45, and it is clearly 11111 * 9), and because 99999 is the largest 5 digit number, it must be the largest 5 digit multiple of 9. 99999 is the greatest no divisible by 9.if u divide it u`ll get 11111.

To check for divisibility by 9 sum the digits of the number and if this sum is divisible by 9 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 9 so 32643 is divisible by 9. As 9 = 3 × 3, any number divisible by 9 is also divisible by 3, thus as 32643 is divisible by 9 it is also divisible by 3. However, for completeness: to check for divisibility by 3 sum the digits of the number and if this sum is divisible by 3 then so is the original number. For 32643: 3 + 2 + 6 + 4 + 3 = 18 which is divisible by 3 so 32643 is divisible by 3.

The divisibility test for the number 9 is: Any number whose digits add up to 9 or a multiple of 9, is divisible by 9. Any other number the sum of whose digits do not add up to 9 or a multiple of 9, are not divisible by 9.For example, the digits of 81 sum up to 9, and therefore, 81 is divisible by 9. The digits of the number 319381482 add up to 39, and therefore, 319381482 is divisible by 9.

345 is not divisible by 9. A quick rule for checking to see if a number is divisible by 9 is to add all of the number's digits. If their sum is divisible by 9, so is the number.2+3+4 = 9, which is divisible by 9, so 234 is divisible by 9. (234/9 = 16)3+4+5 = 123, which is not divisible by 9, so 345 is not divisible by 9 (345/9 = 38 r 3)5+6+7 = 18, which is divisible by 9, so 567 is divisible by 9 (567/9 = 63)