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# Explain how you can break numbers apart to find the product 812?

Updated: 4/27/2024

Wiki User

14y ago

812 !!!

You inspect the number;

1. If it is an EVEN number it will divide by '2'

2. If it ends in '5' or '0' it will divide by '5'

3. If the digits sum to '9' , then it will divide by '9'

4. Without any of the above, try dividing by either '3' or '7'.

5. If none of the above work, keep trying by dividing by prime numbers; 11,13,17,19,23,29, etc.,

For 812 . It is an even number so it will divide by '2'

It does not end in '5' or '0' so will NOT divide by '5'

Its digits 8+1+2 = 11 Do not sum to '9' so will NOT divide by '9'.

So

2)812 = 406

2)406 = 203

'203' is an ODD number so will not divide by '2' . Since it does not end in '5' ot will not divide by '5' . It digits do NOT sum to '9' so will not divide by '9'.

So try '3'

3)203 = 67 remainder '2' Does not divide by '3'

So try '7'

7)203 = 29

So there you have it . 812 breaks down to 2,2,7,& 29. the factors.

When multiplied together 2 x 2 x 7 x 29 = 812 or 4x7 x 29 = 812 or 28 xx 29 = 812

lenpollock

Lvl 15
1mo ago

Wiki User

14y ago

812 = 2 * 2 * 7 * 29

Start dividing the number with any of the prime numbers that divide it properly and continue dividing until you are left with a reminder of 0 or a Prime number.

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