35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7
-6K+7K=1K or K
-6k + 7k = k
-6k+7k = 1k or normally k on its own.
Put it into two binomilals that multipy together to create the polynomial. For example: 5K(squared)-2k-7 is factored out as: (5k+1)(-7K+1)
The answer is 13k .
7k + 4 + 4k - 9 - 5k (7k + 4k - 5k) + (4 - 9) 6k + -5 6k - 5
13k to the power of 2
That equals 13k
k(7k + 9)
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It is: 7k
It simplifies to 7k = 49 which gives k = 7.
No because 0 is additive inverse the multiplicative inverse of a number is when you multiply that number by the m. inverse and still get that number.
Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. The most that you can do is: 13p = 31-7k so that p = (31-7k)/13
7k = 7,000,000 rupees.
Same as subtracting 6 from 7 = K
A 7k is 4.3496 miles.