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35k2 - 22k + 3 = 0 35k2 - 15k - 7k + 3 = 0 5k(7k - 3) - (7k - 3) = 0 (5k - 1)(7k - 3) = 0 5k -1 = 0 or 7k - 3 = 0 5k = 1 or 7k = 3 k = 1/5 or k = 3/7

-6K+7K=1K or K

answer=3k-3

-6k + 7k = k

-6k+7k = 1k or normally k on its own.

Put it into two binomilals that multipy together to create the polynomial. For example: 5K(squared)-2k-7 is factored out as: (5k+1)(-7K+1)

1k

1k

The answer is 13k .

7k + 4 + 4k - 9 - 5k (7k + 4k - 5k) + (4 - 9) 6k + -5 6k - 5

3k-5=7k+73k-7k=7+5-4k=12k=-3

13k to the power of 2

That equals 13k

k(7k + 9)

3k+4m+2

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It is: 7k

It simplifies to 7k = 49 which gives k = 7.

No because 0 is additive inverse the multiplicative inverse of a number is when you multiply that number by the m. inverse and still get that number.

1

Solving equations in two unknowns requires two independent equations. Since you have only one equation there is no solution. The most that you can do is: 13p = 31-7k so that p = (31-7k)/13

7k = 7,000,000 rupees.

Same as subtracting 6 from 7 = K

17k2-4k+19-14k2-16-7k-11k2=-8k2-11k+3

A 7k is 4.3496 miles.