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Q: Factor 9x squared - 6xy plus y squared - 81?

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9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 = (3x - y - 9)*(3x - y + 9)

9x2 - 6xy + y2 - 81 = (3x - y)2 - 92 = (3x - y - 9)(3x - y + 9)

The answer? There is no "answer" There cannot be an answer because they are all different. In order to make calculations, the variables have to be the same. x squared, xy, y squared are the variables, and none of them match. Therefore your "answer" must look like this: 9x squared - 6xy + y squared - 81. Hope I Helped :D

9x^2-6xy+y^2 = (y-3x)^2 (y-3x)^2-81 -> ((y-3x)+9)((y-3x)-9)

(3x - y)(3x - y) - 81

(3x - y + 9)(3x - y - 9)

9x2 - 6xy + y2 - 81 = (3x - y)2 - 81 (since the first three terms make a perfect square = (3x - y - 9)(3x - y + 9) since the expression now is a difference of two squares.

(2x - 9)(2x - 9) or (2x - 9)2

(9x)2 +9x/(45x)2 +81= 9+9x/86

(3x - y - 9)(3x - y + 9)

x2-81 = (x-9)(x+9)

78 minus78

(9 - 5u)(9 + 5u)

117

79, -79

To factor this, find two numbers whose product is 81 and sum 18. These two numbers are therefore 9 and 9. So we can rewrite the polynomial in its factored form as follows: (k+9)(k+9), or "k plus 9 squared"

9 squared equals 81.

The square root of 81 squared is 81.

One: 81 squared = 81^2 = 6561

(2x - 9)(2x +9)

Because: (9-x)(9-x) = 81-18x+x^2

(m + 9)(m + 9)

9 x 9 = 81 9 squared = 81 3 squared times 3 squared = 81

92 = 81122 = 14481 + b2 = 144(take 81 from both sides)b2 = 63b = 7.937253933

9 Squared is 81.Squared means to times a number by itself so..... 9 squared = 9x9 = 81!