answersLogoWhite

0


Best Answer

That doesn't factor neatly. Applying the quadratic formula, we find two imaginary solutions: -8 plus or minus i times the square root of 11.

x = -8 + 3.3166247903554i

x = -8 - 3.3166247903554i

where i is the imaginary square root of -1

User Avatar

Wiki User

8y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

11y ago

This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: Zero plus or minus 4i times the square root of 1

x = 4i, -4i

where i is the square root of -1.

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

x2 - 8x + 12

(x - 6)(x - 2)

x2 - 2x - 6x + 12

x2 - 8x + 12

x - 6 = 0

x = 6

x - 2 = 0

x = 2

Solution set: {2, 6}

This answer is:
User Avatar

User Avatar

Wiki User

13y ago

It is not possible - you can't have two numbers that multiply to get one but add up to four

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

There is no factorisation with real roots. The complex roots are 8 +or- i*sqrt(11) where i is the imaginary square root of -1

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

(x - 2)(x - 2)(x2 + 2x + 4)

This answer is:
User Avatar

User Avatar

Wiki User

8y ago

(x - 4)(x - 2)

This answer is:
User Avatar

User Avatar

Wiki User

11y ago

(x + 7)(x + 5)

This answer is:
User Avatar

User Avatar

Wiki User

12y ago

x-14

This answer is:
User Avatar

User Avatar

Wiki User

14y ago

X((x+1)^2)

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Factor x2 - 6x plus 8?
Write your answer...
Submit
Still have questions?
magnify glass
imp