oh my goodness not even dr.sheldon cooper can answer that
All you have to do is add the numbers and determine how much the numbers change. In your case, the new coordinates are (0, -1), (4, -2), (2, -6).
If the coordinates of the end points are (a,b) and (c,d) then the midpoint is the point whose coordinates are [(a+c)/2, (b+d)/2]
Use Pythagoras' Theorem: calculate the square root of ((difference of x-coordinates)2 + (difference of y-coordinates)2).
The point whose Cartesian coordinates are (2, 0) has the polar coordinates R = 2, Î˜ = 0 .
You find the midpoint of a line segment by dividing its length by two. If you are given two sets of 'x' and 'y' coordinates as the endpoints of the segment on a graph, then you need to use the formula [X1 plus X2]/2, [Y1 plus Y2]/2 to find the coordinates of the midpoint.
To find the midpoint, you find the mean (average) of each direction's coordinates. The average of the x coordinates is (9+7)/2 = 8. The average of y coordinates is (11+8)/2 = 9.5, So the midpoint is (8,9.5). This same method works for 3 and higher dimensions.
Im assuming you mean "how do you find the coordinates of a midpoint", sorry if that is not what you intended. To find the midpoint of two points, you should have two co-ordinates, call them (x1,y1) and (x2,y2). The formula for the co-ordinate of the midpoint is ((x1+x2)/2 , (y1+y2)/2).
Take the average of the x-coordinates, and the average of the y-coordinates.
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
Use the equation: (Y-k)^2 = 4a(X-h)
There is not enough information to provide an answer. You need to know the coordinates of three vertices before you can find the coordinates of the fourth. Otherwise, there are alternative solutions using translations, reflections and rotations.
(y -y1)=(x -x1)(y2 -y1)/(x2 -x1) defines the line containing coordinates (x1,y1) and (x2.y2).
1. Find the coordinates of the center of the circle. Call it point (a, b). To find this point, calculate the average of the x-coordinates of the endpoints, and also the average of the y-coordinates. 2. Find the radius of the circle. Use the formula for distance (which is based on Pythagoras' Theorem). Call the length of the radius "r". 3. The formula for the circle is (x - a)2 + (y - b)2 = r2. Replace the values you found earlier.
1.Finding the solution to a system of linear equations can be found using cartesian coordinates. 2. Graph a circle and you can find the radius using cartesian coordinates.
That depends upon what you are given - the equation of the line, the coordinates of 2 points on the line, etc.
x-intercept = (-6, 0)
You do not have 3 coordinates in the Cartesian plane. The Cartesian plane is a plane and is therefore 2 dimensional. In 2 dimensional space you require only 2 coordinates. 3 coordinates are required to locate a point in 3-dimensional space but then it cannot be a Cartesian PLANE.
The answer is 344.
The point whose Cartesian coordinates are (-3, -3) has the polar coordinates R = 3 sqrt(2), Î˜ = -0.75pi.
The idea is to calculate the average of the x-coordinates (this will be the x-coordinate of the answer), and the average of the y-coordinates (this will be the y-coordinate of the answer).
-1, 2, -2 -2, -1, 2
The coordinates of the mid points are the means of the pairs of coordinates of the two end points. Thus, if P = (px, py, pz) and Q = (qx, qy, qz) then the midpoint of PQ is [(px+qx)/2, (py+qy)/2, (pz+qz)/2]. The result can be simplified for 2-dimensional space, or extended to more dimensions.