To find the equations of the straight lines through the given points, we can use the slope-intercept form (y = mx + b).
For points (3,0) and (0,4): The slope (m = \frac{4 - 0}{0 - 3} = -\frac{4}{3}). Using point (0,4), the equation is (y = -\frac{4}{3}x + 4).
For points (3,-3) and (1,5): The slope (m = \frac{5 - (-3)}{1 - 3} = -4). Using point (3,-3), the equation is (y = -4x + 9).
Thus, the equations are (y = -\frac{4}{3}x + 4) and (y = -4x + 9).
y = 3x-4
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
If you mean points of (-5, 0) and (10, 9) then the slope is 3/5 and the straight line equation is 5y = 3x+15
It is a straight line with no slope with a 'y' intercept of 2
It is: y = 2 which is straight horizontal line with no slope that connects (-1, 2) to (5,2)
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
The equation for the given points is y = x+4 in slope intercept form
It is y = 2.
Y= -3x + 8
Points: (2, 5) and (0, 5) Slope: 0 Equation: x = 2 meaning that it is a straight horizontal line parallel to the y axis
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.