Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
Points: (0, 0) and (10, 30) Slope: 3
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
It is a straight line with no slope with a 'y' intercept of 2
Another set of points are needed to find the slope.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
It's not possible because the given points would be a vertical line parallel to the y axis
That depends on the points in order to find the slope whereas no points have been given.
Assume your points are (x1, y1) and (x2, y2). The slope of a line is its rise (the change in y-coordinates) over its run (the change in x-coordinates). So to find the slope of the line, you substitute the correct values into the formula (y2 - y1) / (x2 - x1).
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
Since the line is horizontal, the slope is zero.
Answer: When there is no slope stated in the function of x, when y=mx+b It simply means y=0x+b Since "b" is the y intercept, your line would be a horizontal line parallel to the X-axis passing through point (0,b) Answer: In other cases, you may need to calculate the slope first, from some other information provided. For example, if you are asked to find the equation that passes through two specified points, you can first find the slope between those two points. Then you can use this slope, and one of the points, with the slope-intercept form of the equation.
No. If you have more than two points for a linear function any two points can be used to find the slope.
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.
The "point slope" formula would be used. This is Y-Y1=m(X-X1) where Y1 and X1 are points the line passes through. M is the slope, so to find the slope of a line perpendicular, take it's opposite reciprocal which would be -8x/9. So Y-(-8)=-8/9(X-18) distribute -8/9 into X-18 and add the 8 on the left side of the = to get the slope intercept form.
Assuming the points are (0, 0) and (10, 30) and that the "-" symbols are to separate the coordinates, (else why -0?) Slope = difference in y coordinate/difference in x coordinate =(30 - 0)/(10 - 0) = 30/10 = 3
Points: (1, 5) and (0, 2) Slope: 3
m= (y2 - y1)/(x2 - x1) m= (4 - 0)/(2 - 0) m = 2