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Find four consecutive odd integers if the product of the smaller two is 112 less than the larger two?
Wiki User
∙ 12y ago
The first 4 consecutive integers can be written as the following:
- X
- X+1
- X+2
- X+3
From the problem the we get the following equation:
2*(X)*(X+3) - {(X)*(X+3)} = 4
2X2+6X - X2 - 3X = 4
X2 + 3X - 4 = 0
Factoring this quadratic equation is (X+4)(X-1) = 0
So the 1st positive integer is X-1 = 0 or X=1
and the other integers is 2,3,4
----Comment by Kirbysuper----
But... those integers aren't positive numbers... in the question, it says to find 4 consecutive positiveintegers.
Wiki User
∙ 13y ago
Wiki User
∙ 12y ago6,8,10,12
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