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If we call the number that we're looking for "x", then we can translate the question like this:

When 15 is subtracted from 7x, the result equals 2x + 10

Or:

7x - 15 = 2x + 10

Then it's a simple matter of simplifying the equation. Group like terms on either side of the equal operator:

7x - 2x = 10 + 15

Then add them together:

5x = 25

And factor five out of both sides:

x = 5

Giving you the answer.

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Q: Find a number such that When 15 is subtracted form 7 times the number the result is 10 more than twice the number?
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