Divided by 4. 2, 1/2 are next.
A 128-sided shape is called a hecatoicosioctagon.
7.019KM ON A BEARING OF 0.989 DEGrEES
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
The third side can be of any length in the interval (2, 128) units of length.
Pythagoras developed the method to solve this- A squared plus B squared equals C squared. A squared= 8x8, added to B squared (also 8x8) So that is 64+64 or 128. So 128 is line C squared. Find the square root of 128, and you have C, which is the diagonal. (Hint- it is 11.31)
128, 512, ...
158 The pattern is t(n+1) = t(n) + 6
128. 1+1=2 2+2=4 4+4= 16 16+16= 32 32+32= 64 64+64 = 128 128+128 = 256 256+256 =512 512+512= 1024 Each time take the answer from the previous problem and double it to find the next number in the sequence.
It is: 158 because each consecutive term is increased by 6.
117 over 128 is already in lowest terms.
128/1000 = 16/125
512 / 2 = 256 256 / 2 = 128 128 / 2 = 64 64 / 2 = 32 32 / 2 = 16 16 / 2 = 8 8 / 2 = 4 4 / 2 = 2 2 / 2 = 1
49/64
i do not know also :(
The number sequence given is 100,135,7,25. The next number would be 498 given this pattern.(35 -128, 18, 47.3, -163,146, 455, 309, 309) the difference of the pattern never converges.
128?
128 = 27