The x-intercepts are quite easy. Just write the equation:
y = (x - 4)(x - 8)
To get the desired y-intercept, you need to multiply this by a scale factor (a constant). Just calculate the y-intercept for the equation as shown above; that will show you by what constant you need to multiply (for example, if the y-intercept is 13, add a factor of 2, to get 26).
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
The greatest possible number of intercepts is: 2 of one axis and 1 of the other axis.The smallest possible number of intercepts is: One of each axis.
Yes
One.
Yes, it is possible only when the x-intercept is infinite. so slope=y/x = 0.
Yes. A quadratic function can have 0, 1, or 2 x-intercepts, and 0, 1, or 2 y-intercepts.
The greatest possible number of intercepts is: 2 of one axis and 1 of the other axis.The smallest possible number of intercepts is: One of each axis.
-7,-25
No because quadratic equations only have 2 X-Intercepts
Yes
The graph must have at least one intercept.
Some do and some don't. It's possible but not necessary.
That's always true if the equation of the line is [ y = any number times x ]. Both intercepts are at the origin. They are x = 0 and y = 0 .
The line intercepts the y-axis at (6,0) It intercepts the x-axis at either (0,4) or (0, -4). It is not possible to be certain because of limitations of the browser used by Answers.com. This means that we cannot see most symbols. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc.
Yes it is possible. The solutions for a quadratic equation are the points where the function's graph touch the x-axis. There could be 2 places to that even if the graph looks different.
Yes. (e.g y=x2-1.)
you can have either one or three x-intercepts, but now 2. because two real roots means 1 imaginary root which is not possible since imaginary roots come in pairs (2,4,6,8...)