Arrange the data in a numerical order.
32 32 33 38 44 46 54 59
The median or the second quartile: (38+44)/2 = 41.
32 32 33 38 | 44 46 54 59
The lower or first quartile: (32+33)/2 = 32.5
32 32 | 33 38 | 44 46 54 59
The upper or third quartile: (46+54)/2 = 50
32 32 | 33 38 | 44 46 | 54 59
No, not all data sets have a mode but all data sets have a mean and median.
First, you add all of the numbers in the set together. Then, you divde the sum by however many numbers there are in the set of data. Your quotient is the average/mean.
find the missing data. (assume that the data items are listed in order from least to greatest.) clues :mean =27 mode =30 Data: 10, 25, 27, ?, 30, ?
To answer this question I will use an example. Data set: 10, 20, 30, 40, 50. First find the sum of all the numbers...so 10+20+30+40+50= 150. Then you take the sum (150) and divide it by the number of numbers in the data set. So 150 divided by 5 (the number of numbers in this data set) = 30. 30= the mean of the above data set. Finding the mean is pretty simple. :)
An outlier
Yes. Usually the value of the lower quantile, median, and upper quantile are in ascending order, how if for the particular set of data, if all values are the same, then these three measures can be the same.
The quartiles for a set of data are three values - the lower quartile, the median and the upper quartile - such that they divide the data set into four parts with an [approximately] equal number of observations in each. Thus:a quarter of all the observations are smaller than the lower quartile,a quarter of all the observations are between the lower quartile and the median,a quarter of all the observations are between the median and the upper quartile, anda quarter of all the observations are greater than the upper quartile.The quartiles for a set of data are three values - the lower quartile, the median and the upper quartile - such that they divide the data set into four parts with an [approximately] equal number of observations in each. Thus:a quarter of all the observations are smaller than the lower quartile,a quarter of all the observations are between the lower quartile and the median,a quarter of all the observations are between the median and the upper quartile, anda quarter of all the observations are greater than the upper quartile.The quartiles for a set of data are three values - the lower quartile, the median and the upper quartile - such that they divide the data set into four parts with an [approximately] equal number of observations in each. Thus:a quarter of all the observations are smaller than the lower quartile,a quarter of all the observations are between the lower quartile and the median,a quarter of all the observations are between the median and the upper quartile, anda quarter of all the observations are greater than the upper quartile.The quartiles for a set of data are three values - the lower quartile, the median and the upper quartile - such that they divide the data set into four parts with an [approximately] equal number of observations in each. Thus:a quarter of all the observations are smaller than the lower quartile,a quarter of all the observations are between the lower quartile and the median,a quarter of all the observations are between the median and the upper quartile, anda quarter of all the observations are greater than the upper quartile.
I could find no data on this guy at all.
all of the above beeeyotch
In reality, a statistician never really has ALL the data. The data is instead taken from a sample of the whole population. If this sample is representative of the entire population, then any statistics based on the sample should be good estimates of the whole but probably not a perfect match. Of course the more data you get from the whole population the better the estimate, but it will always be an estimate unless you census the enitire population.
The value of any element in the third quartile will be greater than the value of any element in the first quartile. But both quartiles will have exactly the same number of elements in them: 250.
yes! Since Q1 = P25 Q2=P50 Q3=P75 Similarly, D1=P10 D2=P20 . . . D9=P90 Where, Q1, Q2, Q3 are lower, median and upper quartiles respectively Dn are the deciles Good Luck~! Sehrish
all of the above - in regards to HIPAA recert
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it when you find all the notes and list .
You can delete a software but a bug or a worm you need to find its base file or do the following. You can format, which will erase all the data from your master and slave drive (if you have one) or partition, which will do the same.
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