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Find the area of a rectangle whose length is 3x 1 and its width is x 2?
Wiki User
∙ 15y ago
I think it's 12x square.
Wiki User
∙ 15y ago
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Find the volume of the rectangular solid whose length is 3 width is 7x and height is y Be sure to include units?
Find the volume of the rectangular solid whose length is 3, width is 7x, and height is y. Be sure to include units.
Can anyone find a formula for the described function A rectangle has a perimeter of 20m Express the area of the rectangle as a function of the length of one of its sides?
Suppose the length and width of the rectangle are L and W metres respectively.Then the perimeter, P = 20 m implies that2(L + W ) = 20 => L + W = 10 or W = 10 - L.Then Area = L * W = L * (10 - L) sq metres.
Find the area of each what A circle of radius 3cm A rectangle that has a length of 14 inches and a width of 2 inches A triangle with a base of 0.4 feet and a height of 0.7 feet?
1. The formula for finding the Area of a circle is Pie X R-squared. R 3 cm squared is 9cm X 3,14 (value of Pie) = 28.26 square inches. 2. The formula for finding the Area of a rectangle is Length X Width (LXW): 14 X 2 = 28 square inches. 3.The answer is...900 ins. are in 75 ft. 24
How do you find diameter of a cylinder?
the width of the cylinder
Find the maximum area of a rectangle inscribed in a circle of radius 12 in?
The length and width of the rectangle (and thus it's area) will be defined by the circle. Specifically, the diagonal of that rectangle will always be equal to the diameter of the circle. To find the maximum area then, one can simply define the rectangle with that relationship, take the derivative of that function, and find out where that comes to a value of zero. The area will be peaked at that point: a = lw d2 = l2 + w2 ∴ l = (d2 - w2)1/2 Remember that the radius is 12, so the diameter is 24, and things can be simplified by plugging that into the equation at this point: l = (576 - w2)1/2 ∴ a = (576 - w2)1/2 w The next step is to take this equation for area, and find it's rate of change with respect to width: ∴ da/dw = (576 - w2)1/2 + 1/2 * (576 - w2)-1/2 * -2w * w ∴ da/dw = (576 - w2)1/2 - (576 - w2)-1/2 * w2 Now let that value equal zero: 0 = (576 - w2)1/2 - (576 - w2)-1/2 * w2 ∴ (576 - w2)1/2 = (576 - w2)-1/2 * w2 ∴ 576 - w2 = w2 ∴ w2 = 576 / 2 ∴ w2 = 288 ∴ w ≈ 16.97 And one can work out the corresponding height: d2 = l2 + w2 ∴ 242 = l2 + 288 ∴ l2 = 576 - 288 ∴ l2 = 288 ∴ l ≈ 16.97 Meaning that the optimum rectangle is a perfect square. To be completely thorough, it should be confirmed that the area found was a maximum and not a minimum. This can be done easily enough by taking a slightly lesser width and a slightly greater width, and seeing how their areas compare: a = (576 - w2)1/2 w Let w = 16 ∴ a = (576 - (16)2)1/2 * 16 ∴ a = 3201/2 * 16 ∴ a = 51/2 * 128 ∴ a ≈ 286.22 Let w = 18 a = (576 - 182)1/2 * 18 ∴ a = 2521/2 * 18 ∴ a = 71/2 * 108 ∴ a ≈ 285.74 Both of these values are less than the area surrounded by the square, so the square's area is indeed a maximum and not a minimum.
What is the area of a rectangle whose length is 9cm and whose width is 8cm?
A rectangle must have two pairs of equal sides. So to find the area of a rectangle, the rule is just length x width.8x9 = 72cm^2
How do you find the length and width of a rectangle?
the length of a rectangle is 8 more than the width. the area os 345 centimeters. find the length and width of the rectangle
How do you find the area of a rectangle whose length is 6cm and width is 4cm?
You multiply 6 and 4.
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
How do you find the length of a rectangle when the width and area are provided?
For a rectangle, area equals length times width. To find the length given the width and area, divide the area by the width.
What is the solution in this problem find the perimeter of a rectangle whose length is 5Cm less than twice its width its width is 15Cm?
80cm.
The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
How do you find the length of rectangle or square if the area and width are known?
For a rectangle or square, Area = Length * Width So Length = Area / Width.
Area of rectangle-?
length times width
How do you find the width of a rectangle if you know its length and area?
Area of rectangle divided by its length = width of rectangle
How do you find the area of a square and a rectangle?
Multiply the length and width to find the area of both a rectangle and square.
