Area of a rhombus = 0.5 times the product of its diagonals
The answer depends on the measure of WHAT! Side length, angles, length of diagonals, area? And the answers to these depend on what information is given.
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
The diagonals of a rhombus cannot be the same size.
If both diagonals are 10 units then the rhombus is, in fact, a square. Its area is 50 square units.
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
It is: 0.5*10*12 = 60 square m
The area of rhombus with diagonals 28Cm square and 28Cm is: 392 cm2
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
Area of rhombus = 0.5 times the product of its diagonals
The area of the rhombus is 40 square feet. To see why, Draw a rectangle encompassing the rhombus with sides parallel to the rhombus' diagonals. The rectangle has dimensions 10 ft X 8 ft = 80 square ft. Using the diagonals as dividers, each quarter of the rectangle is divided into 2 by one of the rhombus' sides. Thus the area of the rhombus is exactly half that of the encompassing rectangle.
Multiply the diagonals and divide by 2
Area of the rhombus: 0.5*8*10 = 40 square feet
The area is 56 cm2
60 square feet.
60 square units.
Yes, they do.
48 sq ft.
AC and DB must be the diagonals of the rhombus, because the sides are all equal. Area = product of the diagonals. = 14 x 8 = 112
Area of a rhombus: base times perpendicular height Or area of a rhombus: 0.5 times product of its diagonals
Area = 30 sq feet
Area = length*perpendicular height or 0.5*the product of its diagonals
1/2 x 8 x 7 = 28cm2