The center of the circle is at (9, 7) on the Cartesian plane
a diameter
The equation for a circle is generally written in the form (x+a)^2+(y+b)^2 = r^2Remember, for the centres for the x and y value, they go in the opposite direction of the rule.So:if the centre is (-2,-4), the equation of the circle is (x+2)^2+(y+4)^2=9
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
measure it
(3, -2) You find the center by taking the opposite of the numbers added to the X and to the Y.
a diameter
Equation of the circle: (x-3)^2 +( y+13)^2 = 169
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
x=9+11=5 11,2
Circumference ("perimeter") of a circle = (pi) x (diameter of the circle)
The equation for a circle is generally written in the form (x+a)^2+(y+b)^2 = r^2Remember, for the centres for the x and y value, they go in the opposite direction of the rule.So:if the centre is (-2,-4), the equation of the circle is (x+2)^2+(y+4)^2=9
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
measure it
(3, -2) You find the center by taking the opposite of the numbers added to the X and to the Y.
Area of a circle = (pi) (R2)R = radius of the circle = 1/2 of its diameter