Assuming that the terms, a and AA, are commutative, It is 1 + a^3 + (AA)^3 - 3aAA
The determinant of the given matrix is -a^3.
relationship between determinant and adjoint
A single math equation does not have a determinant. A system of equations (3x3 , 4x4, etc.) will have a determinant. You can find a determinant of a system by converting the system into a corresponding matrix and finding its determinant.
If it a 2x2 matrix, the determinant is 3*a - (-2)*5 = 3a + 10 = 7 So 3a = -3 so a = -1
For a matrix A, A is read as determinant of A and not, as modulus of A. ... sum of two or more elements, then the given determinant can be expressed as the sum
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There is no easy way to find the determinant; it's long and tedious. There are computer programs available (like MATLAB) that will find the determinant. You'll find there probably won't be a large matrix in an exam if you're required to find the determinant.
1
0 or 1
aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa aa
Put the three points in a matrix with the last column with ones. Then find the determinant, then multiple by .5 Example: (1,1) (2,4)(4,2) 1 1 1 2 4 1 4 2 1 The determinant is: [(1*4*1)+(1*1*4)+(2*2*1)]-[(1*4*4)+(1*2*1)+(1*2*1)]=12-20= -8 Therefore you must multiple by -.5= 4
The genotypic ratio of a cross of Aa and Aa is: one AA, one aa, and two Aa. Or 1:2:1
What is the solution of this question By wronskian determinant method please find whether the solution exist or not where.... y1 = (squre of) cos x, y2 = 1 + cos 2 x.