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Q: Can a number be divisible if it has remainders?

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Not exactly because there will be remainders

It is an odd number

Yes, you get a quotient of 255 which is a whole number and with no remainders.

378 is divisible by both 3 and 9 with no remainders

It can be divided into any of its multiples with no remainders.

1,2,4,5,8,10,20,40,80

They are the numbers divisible into it and leaving no remainders.

Yes, with no remainders

It is divisible by 3 and 5 leaving no remainders

Of course 24815 is divisible by both numbers. Any real number can be divided by any real number except 0. In both cases above, you will get infinitely repeating remainders.

50 is divisable by 1,2,5.10,25,50

No because both numbers will have remainders

Itself and any of its factors because they leave no remainders

Yes and with no remainders

There are 11 possible remainders (1 to 11). If something is divisible by 12, there is said to be no remainder, but this can be considered to be a remainder of 0, making 12 possible remainders.

All of the even numbers are divisible by 2 leaving no remainders

Those that are not divisible by 2 with no remainders.

if one of its factors are a 3 or after dividing a number by 3, their are no remainders There is also another trick: add all of the digits of the number together. The original number is divisible by 3 if and only if the sum of the digits is divisible by 3. For example: 321 is divisible by 3 because 3+2+1=6 and 6 is divisible by 3. 322 is not divisible by 3 because 3+2+2=7 and 7 is not divisible by 3.

Factors of numbers are divisible by them with no remainders

Yes but they will all have remainders

Only 3 non-zero remainders.1, 2, and 3 are the only possible non-zero remainders since any number greater than or equal to the divisor could also be divided, to result in a new quotient. A remainder of zero, means that the dividend is divisible by the divisor (the divisor is a factor of the number)

585 is divisible (without remainders) by: 1, 3, 5, 9, 13, 15, 39, 45, 65, 117, 195, 585.

It could be: x*y = 20 and so 523*20 = 10460 which is divisible by 4 and 5 with no remainders

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.