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Find the probability of a 4 turning up at least once in two tosses of fair die?
Wiki User
∙ 14y ago
Pr(4 turns up at least once in two tosses) = 1 - Pr(4 turns up zero times in two tosses)
= 1 - (5/6)*(5/6) = 1 - 25/36 = 11/36
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∙ 14y ago
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Kalvin tosses a coin five days in a row and gets tails every time Do you think there is something wrong with the coin How can you find out?
There is a 1/16 probability that 5 tosses end with the same result - 1/32 that they are all tails. In this kind of example, most statisticians would not reject the hypothesis of a fair coin unless the probability was less than 5% or 1/20. The null hypothesis is that the coin is a fair coin. If the alternative hypothesis is that something is wrong with the coin, the probability of a result such as the one observed (and its mirror image) is 6.25%. So you would not reject the null hypothesis at the 5% level. However, if your alternative is that the coin favours tails, the probability of as extreme an outcome is 0.03125 or 3.125% and you would reject the null hypothesis. This is a marginal case at the 5% level and you may wish to toss the coin a few more times to reduce the probability of the outcome occurring purely by chance.
How do you find experimental-probability?
To find the experimental probability of an event you carry out an experiment or trial a very large number of times. The experimental probability is the proportion of these in which the event occurs.
Find the probability that in a family of 4 children will be a at least 1 boy and 3 girls?
There is no simple answer to the question because children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the answer is 0.2331.
What is the probability of rolling a 7 or 11 with two dice?
The probability of rolling a 7 with 2 dice is 6/36; probability of rolling an 11 is 2/36. Add the two together to find probability of rolling a 7 or 11 which is 8/36 or 2/9.
Find the probability of each event when two fair number cubes are rolled?
The probability that any number will come up on one cube is 1/6. 1/6*1/6=1/36 the probability is 1/36
Find the probability of heads on three consecutive tosses of a coin?
The number of total outcomes on 3 tosses for a coin is 2 3, or 8. Since only 1 outcome is H, H, H, the probability of heads on three consecutive tosses of a coin is 1/8.
How do you find the probability on a biased coin of getting 3 heads out of 3 coin tosses when the probability of getting a head is 60 percent?
0.63 = 0.216
How can you find a probability expressed as a percentage from a punnett square?
You can find probability form a Punnett square by turning fractions into percents
How can you find a probability expressed as a percentage from punnett square?
You can find probability form a Punnett square by turning fractions into percents
What is the probability that at least 1 head appears in 7 tosses of a fair coin?
To find P( at least 1 head in 7 tosses) we can find P( no heads) and subtract that from one. Alternatively, we need to find P ( 1 head) + P ( 2 heads )+...+ P(7 heads) Since P of no heads is P( all tails) this is (1/2)7 =.0078125 ( 1/128 as a fraction) Now 1-(1/128)=127/128 or .9921875
When A fair coin is tossed three times. Find the probability of getting a head on the first toss and tails on the second and third tosses?
It is 1/8.
A coin is tossed 5 times find the probability that the 6th toss is a tail given tht the first 5 tosses were all tails?
The chance is 50%-50% that it will be heads or tails; this does not change regardless of the number of previous tosses and their results.
Math question!: The experimental probability of flipping a red-yellow counter and landing on yellow is 9/16 . If the counter landed on red 35 times, find the number of tosses?
Ok if the probability of getting yellow is 9/16 then the prob of getting red is 7/16. If we got red 35 times during the experiment that means the number of tosses was 80. Since 35/n = 7/16 where n = the number of tosses Answer: n = 80 tosses
Find the probability that in 5 tosses of a fair die a 3 appears at no one time?
Possible outcomes per each toss = 6Number of them that are not a 3 = 5Probability of no 3 in one toss = 5/6.Probability of no 3 in 5 tosses = (5/6) x (5/6) x (5/6) x (5/6) x (5/6) = 3,125/7,776 = 0.40188 = 40.19%(rounded)
Find the probability that in a family of 4 children will be a at least 1 boy b At least 1 boy and 1 girl Assume that the probability of a male birth is 12?
http://answerboard.cramster.com/statistics-and-probability-topic-5-292446-0.aspx
When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?
This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %
When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?
Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32
