Points: (0, 0) and (10, 30)
Slope: 3
Assuming the points are (0, 0) and (10, 30) and that the "-" symbols are to separate the coordinates, (else why -0?)
Slope = difference in y coordinate/difference in x coordinate
=(30 - 0)/(10 - 0) = 30/10 = 3
Slope is "Rise over Run"
Run is in the X direction (10 in the question)
Rise is in the Y direction (30 in the question)
30 / 10 = 3
Slope = 3
1/3
(6,2) (1,5)
1
It's not possible because the given points would be a vertical line parallel to the y axis
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
m= (y2 - y1)/(x2 - x1) m= (4 - 0)/(2 - 0) m = 2
Since the line is horizontal, the slope is zero.
y=mx+b
1
No
2
1
2222
Not always. For example, try to find the slope of the line that passes through the points (3, 4) and (2, 3).
To find the slope of a line passing through two points, use the formula (y2 - y1) / (x2 - x1). In this case, the two points are (17, 101). Since there is only one given point, it is not possible to find the slope of the line passing through these points.
It is a straight line with no slope with a 'y' intercept of 2
Slope, m, equals (y2-y1)/(x2-x1). Slope is (8-2)/(8-2) or 1.
Slope, m, equals (y2-y1)/(x2-x1). Slope is (0-(-1))/(0-(-1)) or 1/1 or 1.
The slope of a line can be found using the formula: m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are two points on the line. For the line that passes through the points A(-2, -1) and B(3, 5), we have: m = (y2 - y1) / (x2 - x1) = (5 - (-1)) / (3 - (-2)) = 6 / 5 = 1.2 So the slope of the line that passes through the points A(-2, -1) and B(3, 5) is 1.2.