It has no solutions because the discriminant is less than zero.
The solutions are: x = 4, y = 2 and x = -4, y = -2
No. It's a quadratic equation, and it has two solutions.
If: 2x+y = 5 and x2-y2 = 3 Then the solutions work out as: (2, 1) and ( 14/3, -13/3)
These are two expressions, not equations. Expressions do not have solutions, only equations do. NB equations include the equals sign.
It is a quadratic equation and its solutions are: x = 4 or x = -9
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
-x2+2.5x+1=0 x=-0.350781 x=2.85078
1, that works, right?
It is the pythagorean theorem. Used in finding the lengths of sides of right angled triangles.
There are no real solutions. The discriminant (b squared -4ac) is less than 0, so there are 2 imaginary solutions and 0 real ones.
b = 14324.80366
X = √63
A squared plus B squared equals C squared. It is the Pythagorean theorem.To do this you would find the two short sides of a right triangle. Then for one short side find the length and multiply it by itself and for the other short side do the same thing. After that add those two up and and find the square root of it. That number you have there is C aka hypotenuse aka the long side. :)
ax2+bx+c = 0 is the general form of a quadratic equation which normally has two solutions
It is: 3x2+6x-11 = 0
Quadratic formula gives roots as 1.53 and 10.47 (to nearest hundredth.)
There is a ninja behind you
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.